47 lines
974 B
C++
47 lines
974 B
C++
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/*
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Description: A program to reverse the digits of a number.
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Approach: Running a while loop over number till it becomes 0
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Multiplying the result variable to 10 each time.
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Taking the modulus of number at every iteration and adding it to the final result to generate the reverse.
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Dividing the number by 10 at every iteration.
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*/
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#include <iostream>
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using namespace std;
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//function
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long reverse_digit(long n)
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{
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//result variable
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long num = 0;
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while (n != 0)
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{
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//storing the last digit of n in temp variable
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long temp = n % 10;
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//multiplying the num variable into 10 and adding temp value to it
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num = num * 10 + temp;
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//Dividing n by 10 at each iteration
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n = n / 10;
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}
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return num;
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}
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//main starts
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int main()
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{
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cout << "Enter a number\n";
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long n;
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cin >> n;
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cout << "Reverse number is: ";
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cout << reverse_digit(n);
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}
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/*
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Input:
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Enter a number
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1234
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Output:
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Reverse number is: 4321
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*/
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