DSA/stacks/java/the-stock-span-problem.java

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Java
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import java.lang.reflect.Array;
import java.util.Arrays;
import java.util.Stack ;
/**
* Problem statement :
* The stock span problem is a financial problem where we have a series of n daily price quotes for a stock
* and we need to calculate span of stocks price for all n days.
* The span Si of the stocks price on a given day i is defined as the maximum number of consecutive days just before the given day,
* for which the price of the stock on
* the current day is less than or equal to its price on the given day.
* For example, if an array of 7 days prices is given as {100, 80, 60, 70, 60, 75, 85}, then the span values for corresponding
* 7 days are {1, 1, 1, 2, 1, 4, 6}
*/
class The_Stock_Span_Problem extends stack{
public The_Stock_Span_Problem(int Max) {
super(Max);
}
/**
* this problem is being solved with stack abstract data type.
*/
public void problem(int[] price,int n,int[] span){
stack st = new stack(Max);
st.push(0);
//span of the first day is always going to be 1
span[0] = 1;
for (int i = 1;i < n;i ++){
span[i] = 1;
st.PrintStack();
while(!st.isEmpty() && price[st.top()] <= price[i]){
st.pop();
}
if (st.isEmpty()){
span[i] = i + 1;
}
else{
span[i] = i - st.top();
}
st.push(i);
}
printArray(span);
}
public void printArray(int[] span){
System.out.println("The span of the stock array :" + Arrays.toString(span));
}
/**
* This is a different approach that has slightly higher time complexity than the approach used above
* Both the methods are awesome and star struck but...xD
*/
public void alternate_approach(int[] price,int n,int[] span){
Stack<Integer> sta = new Stack<>();
span[0] = 1;
for (int i = 1;i < n;i++){
for (int j = 0;j < i;j++){
sta.push(j);
}
while(!sta.isEmpty() && price[sta.peek()] <= price[i]){
sta.pop();
}
if (sta.isEmpty()){
span[i] = i + 1;
}
else{
span[i] = i - sta.peek();
}
sta.clear();
}
printArray(span);
}
}
class Main {
//to test the span stock problem
public static void main(String[] args){
int[] price = { 10, 4, 5, 90, 120, 80 };
int n = price.length;
int[] span = new int[n];
The_Stock_Span_Problem prob = new The_Stock_Span_Problem(1000);
prob.alternate_approach(price,n,span);
}
}