54 lines
1.1 KiB
C++
54 lines
1.1 KiB
C++
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/*
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Description: Given an vector v containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the vector.
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Approach: Using for loop from 0 to n and searching if the value is present in the vector or not using find() function.
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If a certain value is not present, the function will return it.
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*/
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#include <iostream>
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#include <vector>
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#include <algorithm>
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using namespace std;
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//function starts
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int missingNumber(vector<int> &v){
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int num;
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for(int i=0;i<=v.size();i++){
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//checking if i is present or not in the vector
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//if not present,it will store the value of i in the num variable and breaking it
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if(find(v.begin(),v.end(),i)==v.end()){
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num=i;
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break;
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}
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}
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return num;
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}
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//main starts
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int main() {
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cout << "Enter number of elements:\n";
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int n;
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cin>>n;
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vector<int> v(n);
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cout<<"Enter any "<<n<<" elements (From 0 to "<<n<<") \n";
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for(int i=0;i<n;i++){
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cin>>v[i];
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}
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cout<<"\nMissing number is: "<<missingNumber(v);
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return 0;
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}
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/*
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Input:
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Enter number of elements:
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4
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Enter any 4 elements (From 0 to 4)
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0
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1
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2
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3
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Output:
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Missing number is: 4
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*/
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