24 lines
958 B
JavaScript
24 lines
958 B
JavaScript
|
function binarySearch(value, list) {
|
||
|
let first = 0; //left endpoint
|
||
|
let last = list.length - 1; //right endpoint
|
||
|
let position = -1; // After looping if the search item is not found, we will return -1
|
||
|
let found = false; // When item is found we set its value to true
|
||
|
let middle;
|
||
|
|
||
|
while (found === false && first <= last) {
|
||
|
middle = Math.floor((first + last)/2);
|
||
|
if (list[middle] == value) { // If the element is present at the middle itself
|
||
|
found = true;
|
||
|
position = middle;
|
||
|
} else if (list[middle] > value) { //if in lower half
|
||
|
last = middle - 1;
|
||
|
} else { //in in upper half
|
||
|
first = middle + 1;
|
||
|
}
|
||
|
}
|
||
|
return position;
|
||
|
}
|
||
|
|
||
|
console.log(binarySearch(6,[2, 6, 8])); //expected output = 1
|
||
|
console.log(binarySearch(10,[2, 3, 10, 14])); //expected output = 2
|
||
|
console.log(binarySearch(1,[2, 6, 8])); //expected output = -1
|