From 2332f219916eaea29600fe0b32caad1fd334e4e9 Mon Sep 17 00:00:00 2001
From: Riya Ranka <81897389+RiyaRanka@users.noreply.github.com>
Date: Mon, 24 Jul 2023 12:28:46 +0530
Subject: [PATCH] Update Kadane's-Algorithm.cpp

---
 .../CPlusPlus/Arrays/Kadane's-Algorithm.cpp   | 19 ++++++++++++++++++-
 1 file changed, 18 insertions(+), 1 deletion(-)

diff --git a/algorithms/CPlusPlus/Arrays/Kadane's-Algorithm.cpp b/algorithms/CPlusPlus/Arrays/Kadane's-Algorithm.cpp
index ee05eb3d..eb839bf2 100644
--- a/algorithms/CPlusPlus/Arrays/Kadane's-Algorithm.cpp
+++ b/algorithms/CPlusPlus/Arrays/Kadane's-Algorithm.cpp
@@ -61,6 +61,21 @@ int max_subarray_sum_method_3(int arr[],int n)
         }
         return maxi;
 }
+// optimized version kadane's algo with one loop
+long long max_subarray_sum_method_4 (int arr[],int n) {  //used for long and big values or integers
+    long long sum,maxi=0; //declaring variables
+    for (int i=0; i<size; i++) {
+        maxi= maxi+arr[i];  
+        if (sum<maxi) {  //if maxSum is greater then maxElement then the maxSum == maxElement 
+            sum=maxi;
+        }
+        else if (maxi<0) { //if elements in array is 0 then return 0
+            sum=0;
+        }
+    }
+    cout<<"\nUsing Kadane's Algoritham maximum sum of subarray is: "<<sum;
+    return 0;
+}
 
 int main()
 {
@@ -75,8 +90,10 @@ int main()
  int ans1=max_subarray_sum_method_1(arr,n);//this is brute force approach time complexity=O(n^3) || space complexity=O(1);
  int ans2=max_subarray_sum_method_2(arr,n);//this is optimized brute force approach time complexity=O(n^2) || space complexity=O(1);
  int ans3=max_subarray_sum_method_3(arr,n);//this is further optimized approach called "Kadane's Algorithm" time complexity=O(n)|| space complexity=O(1);
+ int ans4=max_subarray_sum_method_4(arr,size);//this is optimized approach time complexity=O(n) || space complexity=O(1);
  cout<<"max_subarray_sum:"<<ans1<<endl;
  cout<<"max_subarray_sum:"<<ans2<<endl;
- cout<<"max_subarray_sum:"<<ans3<<endl;//print any ans1,ans2,ans3;
+ cout<<"max_subarray_sum:"<<ans3<<endl;
+ cout<<"max_subarray_sum:"<<ans4<<endl; //print any ans1,ans2,ans3,ans4;
 }