chore: allocate minimum number of pages (#252)

algorithms/Java/README.md

@@ -1,15 +1,18 @@
 # Python
 
 ## Arrays
+
 1. [Counting Inversions](arrays/counting-inversions.java)
 2. [Kadanes Algorithm](arrays/kadanes-algorithm.java)
 3. [Left Rotation](arrays/left-rotation.java)
 4. [Unique Digits of Large Number](arrays/unique-digits-of-large-number.java)
 
 ## Graphs
+
 1. [Dijkstras](graphs/dijkstras.java)
 
 ## Linked Lists
+
 1. [Circular](linked-lists/circular.java)
 2. [Clone Linked List](linked-lists/clone-linkedlist.java)
 3. [Doubly](linked-lists/doubly.java)
@@ -17,19 +20,24 @@
 5. [Singly](linked-lists/singly.java)
 
 ## Queues
+
 1. [Circular Queue using Linked List](queues/circular-queue-linked-list.java)
 2. [Queue using Linked List](queues/queue-linked-list.java)
 
 ## Scheduling
+
 1. [Multi-Level Queue Scheduling](scheduling/multi-level-queue-scheduling.java)
 2. [Rund Robin](scheduling/round-robin.java)
 
 ## Searching
+
 1. [Binary Search](searching/binary-search.java)
 2. [Jump Search](searching/jump-search.java)
 3. [Linear Search](searching/linear-search.java)
+4. [Allocate minimum number of pages](searching/allocate-min-pages.java)
 
 ## Sorting
+
 1. [Bubble Sort](sorting/bubble-sort.java)
 2. [Counting Sort](sorting/counting-sort.java)
 3. [Heap Sort](sorting/heap-sort.java)
@@ -39,11 +47,13 @@
 7. [Selection Sort](sorting/selection-sort.java)
 
 ## Stacks
+
 1. [Balanced Parenthesis](stacks/balanced-paranthesis.java)
 2. [Stack](stacks/stack.java)
 3. [The Stock Span Problem](stacks/the-stock-span-problem.java)
 
 ## Strings
+
 1. [KMP](strings/kmp.java)
 2. [Palindrome](strings/palindrome.java)
 3. [Rabin Krap](strings/rabin-karp.java)
@@ -52,4 +62,5 @@
 6. [Tokenizer](strings/tokenizer.java)
 
 ## Trees
-1. [Pre in Post Traversal](trees/pre-in-post-traversal.java)
+
+1. [Pre in Post Traversal](trees/pre-in-post-traversal.java)

algorithms/Java/searching/allocate-min-pages.java

@@ -0,0 +1,77 @@
+/* QUESTION:
+You are given N number of books. Every ith book has pages[i] number of pages. 
+You have to allocate books to M number of students. There can be many ways or permutations to do so. 
+In each permutation, one of the M students will be allocated the maximum number of pages.
+Out of all these permutations, the task is to find that particular permutation in which the maximum number of pages allocated to a student is minimum of those in all the other permutations and print this minimum value.
+Each book will be allocated to exactly one student. Each student has to be allocated at least one book. */
+
+import java.io.*;
+import java.util.*;
+class GFG {
+	public static void main (String[] args) {
+		Scanner sc=new Scanner(System.in);
+		int t=sc.nextInt();  //number of test cases
+		while(t-->0){
+		    int N=sc.nextInt();
+		    int pages[]=new int[N];
+		    
+		    for(int i=0;i<N;i++){
+		        pages[i]=sc.nextInt();
+		    }
+		    int M=sc.nextInt();
+		    System.out.println(findPages(pages,N, M));
+		}
+	}
+
+    public static int findPages(int[]arr,int n,int m)
+    {
+        if(n<m) return -1;
+        int sum=0;
+        for(int i=0;i<n;i++){
+            sum+=arr[i];
+        }
+        int start=0, end=sum;
+        int res = Integer.MAX_VALUE;
+        while(start<=end){
+            int mid = start+(end-start)/2;
+            if(isPossible(arr, n, m, mid)){
+                res = Math.min(res, mid);
+                end = mid-1;
+            }
+            else start=mid+1;
+        }
+        return res;
+    }
+    public static boolean isPossible(int arr[], int n, int m, int curr_min){
+        int student=1;
+        int curr_sum=0;
+        for(int i=0;i<n;i++){
+            if(arr[i]>curr_min) return false;
+            if(curr_sum+arr[i]>curr_min){
+                student++;
+                curr_sum = arr[i];
+                if(student>m) return false;
+            }
+            else curr_sum+=arr[i];
+        }
+        return true;
+    }
+}
+
+/* 
+Input:
+N = 4
+A[] = {12,34,67,90}
+M = 2
+
+Output:
+113
+
+Explanation: 
+Allocation can be done in following ways:
+{12} and {34, 67, 90} Maximum Pages = 191
+{12, 34} and {67, 90} Maximum Pages = 157
+{12, 34, 67} and {90}  Maximum Pages =113
+Therefore, the minimum of these cases is 
+113, which is selected as the output.
+ */