chore(Java) : add ternery search (#850)

* Add Ternery-search in java

* Updated Ternery Search

Added Time compleities and iterative method of the ternery search.

* Updated Ternery-Search

* Updated Ternery Search

Updated Again.
pull/865/head
Vishnu Rai 2022-10-01 02:37:07 +05:30 committed by GitHub
parent b67f5e1786
commit b4cd97f55a
No known key found for this signature in database
GPG Key ID: 4AEE18F83AFDEB23
2 changed files with 143 additions and 0 deletions

View File

@ -54,6 +54,7 @@
- [Allocate minimum number of pages](searching/allocate-min-pages.java)
- [Exponential Search](searching/Exponential-search.java)
- [Interpolation Search](searching/interpolation-search.java)
- [Ternery Search](searching/ternery-search.java)
## Sorting

View File

@ -0,0 +1,142 @@
// Java program to illustrate
// the iterative approach to ternary search
//
class main {
// Function to perform Ternary Search
// recursive Function
// Time Complexity: O(log3n)
// Auxiliary Space: O(log3n)
static int ternarySearchRecursive(int l, int r, int key, int ar[])
{
while (r >= l) {
// Find the mid1 mid2
int mid1 = l + (r - l) / 3;
int mid2 = r - (r - l) / 3;
// Check if key is present at any mid
if (ar[mid1] == key) {
return mid1;
}
if (ar[mid2] == key) {
return mid2;
}
// Since key is not present at mid,
// check in which region it is present
// then repeat the Search operation
// in that region
if (key < ar[mid1]) {
// The key lies in between l and mid1
r = mid1 - 1;
}
else if (key > ar[mid2]) {
// The key lies in between mid2 and r
l = mid2 + 1;
}
else {
// The key lies in between mid1 and mid2
l = mid1 + 1;
r = mid2 - 1;
}
}
// Key not found
return -1;
}
// Function to perform Iterative Ternary Search
// Time Complexity: O(log3n), where n is the size of the array.
// Auxiliary Space: O(1)
static int ternarySearchIterative(int l, int r, int key, int ar[])
{
while (r >= l) {
// Find the mid1 mid2
int mid1 = l + (r - l) / 3;
int mid2 = r - (r - l) / 3;
// Check if key is present at any mid
if (ar[mid1] == key) {
return mid1;
}
if (ar[mid2] == key) {
return mid2;
}
// Since key is not present at mid,
// check in which region it is present
// then repeat the Search operation
// in that region
if (key < ar[mid1]) {
// The key lies in between l and mid1
r = mid1 - 1;
}
else if (key > ar[mid2]) {
// The key lies in between mid2 and r
l = mid2 + 1;
}
else {
// The key lies in between mid1 and mid2
l = mid1 + 1;
r = mid2 - 1;
}
}
// Key not found
return -1;
}
// Driver code
public static void main(String args[])
{
int l, r, p, key;
// Get the array
// Sort the array if not sorted
int ar[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
// Starting index
l = 0;
// length of array
r = 9;
// Checking for 5
// Key to be searched in the array
key = 5;
// Search the key using ternarySearch
p = ternarySearchRecursive(l, r, key, ar);
// Print the result
System.out.println("Index of " + key + " is " + p);
// Checking for 50
// Key to be searched in the array
key = 50;
// Search the key using ternarySearch
p = ternarySearchIterative(l, r, key, ar);
// Print the result
System.out.println("Index of " + key + " is " + p);
}
}