chore(Rust): add merge sort (#403)
* Add merge sort algorithm
* add rust files to gitignore
* Revert "add rust files to gitignore"
This reverts commit d6a1ab819b
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* Move gitignore to cargo project
* create readme for merge sort
* add merge sort
pull/407/head
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# Rust
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1. [Palindrome Check](strings/palindrome/README.md)
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2. [Merge Sort](sorting/merge-sort/README.md)
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### Rust
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Cargo.lock
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# Rust compiled output
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target
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[package]
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name = "merge-sort"
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version = "0.1.0"
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authors = ["Akshat Adsule <30205531+AkshatAdsule@users.noreply.github.com>"]
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edition = "2018"
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# See more keys and their definitions at https://doc.rust-lang.org/cargo/reference/manifest.html
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[dependencies]
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rand = "0.8.3"
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This sorts an array using Merge Sort. The sort is generic and will work with with any `Vec` whose items have the `std::cmp::Ord ` and `Copy` traits. More information about Merge Sort can be found [here](https://en.wikipedia.org/wiki/Merge_sort)
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## Prerequisites
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- Rust (https://rust-lang.org)
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## Instructions for running the project
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- Open a terminal/powershell window in the folder/directory.
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- Run the following command
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```bash
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cargo run --release
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```
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use rand::{distributions::Uniform, Rng};
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fn main() {
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// Create random numbers
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let range = Uniform::from(0..=100);
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let values: Vec<i32> = rand::thread_rng().sample_iter(&range).take(100).collect();
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println!("Sorting: {:?}",values);
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let result = merge_sort(values);
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println!("Sorted: {:?}", result);
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}
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// Limit type to only objects that can be ordered, cloned and copied
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fn merge_sort<T: std::cmp::Ord + Copy>(nums: Vec<T>) -> Vec<T> {
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// If array only has one item, it is already sorted :-)
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if nums.len() == 1 {
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return vec![nums[0]];
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}
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// If array has 2 items, just compare the values and sort
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if nums.len() == 2 {
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if nums[0] <= nums[1] {
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return vec![nums[0], nums[1]];
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} else {
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return vec![nums[1], nums[0]];
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}
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}
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// Split into 2
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let half = nums.len() / 2;
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let mut left = merge_sort((&nums[0..half]).to_vec());
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let mut right = merge_sort((&nums[half..]).to_vec());
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let mut sorted: Vec<T> = Vec::new();
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loop {
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// If either array is empty, the values in the other array must be larger
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// and so we should dump the remaining array's content into the sorted array
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if left.is_empty() {
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for i in right {
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sorted.push(i);
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}
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break;
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}
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if right.is_empty() {
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for i in left {
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sorted.push(i);
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}
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break;
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}
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// Merge arrays
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if left[0] >= right[0] {
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sorted.push(right[0]);
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right.remove(0);
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continue;
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}
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if left[0] <= right[0] {
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sorted.push(left[0]);
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left.remove(0);
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continue;
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}
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}
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// return sorted array
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sorted
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}
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