add Bingo sort to pull request.

Time complexity and other details explained in comments.

bingo_sort.py

@@ -0,0 +1,56 @@
+# Python implementation of Bingo Sort.
+# This algorithm is derived from simple
+# Selection Sort, but runs on  average and worst case
+# O(m * n) where m=number of distinct elements and N
+# is the size of the array or list. Performs best when
+# repetition of every element is high in the array.
+# Peforms better than quick sort, merge and heap sort
+# if m < log n. 
+
+# Function to print the Array
+def printArray(arr):
+	print("Sorted Array: ",end="")
+	for ele in arr:
+		print(ele, end=" ")
+	print()
+
+# function for Sorting the Array
+def bingoSort(arr, size):
+
+	# Finding the smallest element From the Array
+	bingo = min(arr)
+	
+	# Finding the largest element from the Array
+	largest = max(arr)
+	nextBingo = largest
+	nextPos = 0
+	while bingo < nextBingo:
+	
+		# Will keep the track of the element position to
+		# shifted to their correct position
+		startPos = nextPos
+		for i in range(startPos, size):
+			if arr[i] == bingo:
+				arr[i], arr[nextPos] = arr[nextPos], arr[i]
+				nextPos += 1
+				
+			# Here we are finding the next Bingo Element
+			# for the next pass
+			elif arr[i] < nextBingo:
+				nextBingo = arr[i]
+		bingo = nextBingo
+		nextBingo = largest
+	
+	# Printing the ELements of the Sorted Array
+	printArray(arr)
+		
+arr = [ 5, 4, 8, 5, 4, 8, 5, 4, 4, 4 ]
+bingoSort(arr, size = len(arr))
+
+arr2 = [ 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 ]
+bingoSort(arr2, size = len(arr2))
+
+arr3 = [ 0, 1, 0, 1, 0, 1 ]
+bingoSort(arr3, size = len(arr3))
+
+