Update Add-Two-linkedlist.cpp
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@ -1,7 +1,7 @@
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/* In this algorithm two linked list is given in which we have to add both the linked list and store the output in another linked list.
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Time Complexity: O(m+n) where m and n are the sizes of given two linked lists.
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Space Complexity: O(m) if (m>n) and O(n) if (n>m) ,where m and n are the size of the given two linked list.*/
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Time Complexity: O(m+n) where m and n are the sizes of given two linked lists.
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Space Complexity: O(m+n) where m and n are the size of the given two linked list.
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Space Complexity: O(m) if (m>n) and O(n) if (n>m) ,where m and n are the size of the given two linked list.*/
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@ -12,13 +12,11 @@ class Node
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public:
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int data;
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Node *next;
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Node(int val)
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{
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this->data = val;
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this->next = NULL;
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}
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~Node()
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{
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int value = this->data;
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@ -30,7 +28,6 @@ public:
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cout << "Memory is free for the node with data" << value << endl;
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}
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};
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void insertAtHead(Node *&head, int data)
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{
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Node *temp = head;
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@ -42,10 +39,9 @@ void insertAtHead(Node *&head, int data)
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newNode->next = head;
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head = newNode;
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}
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void insertAtTail(Node *&head, int d)
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{
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// new node create
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if (head == NULL)
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{
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insertAtHead(head, d);
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@ -54,7 +50,6 @@ void insertAtTail(Node *&head, int d)
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head->next = temp;
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head = temp;
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}
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void display(Node *&head)
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{
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if (head == NULL)
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@ -70,7 +65,6 @@ void display(Node *&head)
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}
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cout << "NULL" << endl;
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}
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Node *reverse(Node *head)
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{
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Node *curr = head;
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@ -85,7 +79,6 @@ Node *reverse(Node *head)
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}
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return prev;
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}
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Node *Sum(Node *head1, Node *head2)
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{
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head1 = reverse(head1);
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@ -104,7 +97,6 @@ Node *Sum(Node *head1, Node *head2)
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head1 = head1->next;
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head2 = head2->next;
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}
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while (head1 != NULL)
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{
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int sum = head1->data + carry;
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@ -129,30 +121,23 @@ Node *Sum(Node *head1, Node *head2)
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int digit = sum % 10;
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temp->next = new Node(digit);
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temp = temp->next;
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carry = sum / 10;
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}
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return reverse(ans->next);
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}
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int main()
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{
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Node *node1 = new Node(9);
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Node *head = node1;
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Node *tail = node1;
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insertAtTail(tail, 9);
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insertAtTail(tail, 3);
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insertAtTail(tail, 4);
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insertAtTail(tail, 5);
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insertAtTail(tail, 6);
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cout << "The first Linked List" << endl;
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display(head);
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cout << endl;
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Node *node2 = new Node(5);
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Node *head1 = node2;
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Node *tail1 = node2;
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@ -161,28 +146,17 @@ int main()
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insertAtTail(tail1, 8);
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cout << "The second Linked List" << endl;
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display(head1);
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Node *temp = Sum(head, head1);
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cout << "The sum of the given two linked list" << endl;
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display(temp);
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return 0;
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}
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/*output:
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/*output:
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The first Linked List
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9-> 9-> 3-> 4-> 5-> 6-> NULL
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The second Linked List
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5-> 6-> 4-> 8-> NULL
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The sum of the given two linked list
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9-> 9-> 9-> 1-> 0-> 4-> NULL */
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