Friday, August 18, 2023, 20:00:01 + 6
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@ -54,7 +54,7 @@
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"id": "11fc0a75dace010f",
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"type": "markdown",
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@ -197,10 +197,11 @@
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"omnisearch:Omnisearch": false
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"omnisearch:Omnisearch": false
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"Coding Tips (Classical)/Terminal Tips/Servers/Physical Servers/Raspberry Pis.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Cloud Servers/About Cloud Servers.md",
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"Proof of a formula for modulo.md",
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"Proof of a formula for modulo.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Physical Servers/Raspberry Pis.md",
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"Coding Tips (Classical)/Terminal Tips/Languages/LaTeX.md",
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"Coding Tips (Classical)/Terminal Tips/Languages/LaTeX.md",
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"Machine Tips (Quantum)/Math/Visualizing the Quantum Space.md",
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"Machine Tips (Quantum)/Math/Visualizing the Quantum Space.md",
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"Machine Tips (Quantum)/Math/Quantum Formalism.md",
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"Machine Tips (Quantum)/Math/Quantum Formalism.md",
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@ -209,7 +210,6 @@
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"Coding Tips (Classical)/Terminal Tips/Servers/Virtual Machines/About Virtual Machines.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Virtual Machines/About Virtual Machines.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Virtual Machines/Connect to a VirtualBox VM desktop remotely.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Virtual Machines/Connect to a VirtualBox VM desktop remotely.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/About Servers.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/About Servers.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Cloud Servers/About Cloud Servers.md",
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"Coding Tips (Classical)/Terminal Tips/Servers/Virtual Machines",
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"Coding Tips (Classical)/Terminal Tips/Servers/Virtual Machines",
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"Coding Tips (Classical)/Terminal Tips/GUIs/Tools/Extensions.md",
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"Coding Tips (Classical)/Terminal Tips/GUIs/Tools/Extensions.md",
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"Coding Tips (Classical)/Terminal Tips/GUIs/Tools/Progressive Web Apps.md",
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"Coding Tips (Classical)/Terminal Tips/GUIs/Tools/Progressive Web Apps.md",
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@ -41,4 +41,12 @@ $$((amodp)b)modp=abmodp$$
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Now let a as $3^{24}$, and b as 54 in formula (1):
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Now let a as $3^{24}$, and b as 54 in formula (1):
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$$3^{24×54}\ mod \ 17=((3^{24})^{54}) \ mod \ 17=((324mod17)54)mod17=1654mod17$$
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$$
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\\
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\\begin{align}
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3^{24×54}\ mod \ 17=((3^{24})^{54}) \ mod \ 17 \\ \\&= ((3^{24} \ mod \17)^{54})mod 17
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\end{align}
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= 16^{54}mod17$$
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